Resolva a integral tripla de coordenadas esféricas da função abaixo:

$$\begin{gathered} f\left( \theta , \varphi , \rho \right)=\frac{1}{\rho .sen\varphi } limitada por\left\{\begin{array}{l} 0\le \theta \le 2.\mathrm{\pi } \\ \raisebox{1ex}{$\mathrm{\pi }$}\!\left/ \!\raisebox{-1ex}{$6$}\right.\le \varphi \le \raisebox{1ex}{$\mathrm{\pi }$}\!\left/ \!\raisebox{-1ex}{$4$}\right.\\ 0\le \rho \le 2\end{array}\right. \end{gathered}$$